x^2+26x+29=0

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Solution for x^2+26x+29=0 equation:


Simplifying
x2 + 26x + 29 = 0

Reorder the terms:
29 + 26x + x2 = 0

Solving
29 + 26x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-29' to each side of the equation.
29 + 26x + -29 + x2 = 0 + -29

Reorder the terms:
29 + -29 + 26x + x2 = 0 + -29

Combine like terms: 29 + -29 = 0
0 + 26x + x2 = 0 + -29
26x + x2 = 0 + -29

Combine like terms: 0 + -29 = -29
26x + x2 = -29

The x term is 26x.  Take half its coefficient (13).
Square it (169) and add it to both sides.

Add '169' to each side of the equation.
26x + 169 + x2 = -29 + 169

Reorder the terms:
169 + 26x + x2 = -29 + 169

Combine like terms: -29 + 169 = 140
169 + 26x + x2 = 140

Factor a perfect square on the left side:
(x + 13)(x + 13) = 140

Calculate the square root of the right side: 11.832159566

Break this problem into two subproblems by setting 
(x + 13) equal to 11.832159566 and -11.832159566.

Subproblem 1

x + 13 = 11.832159566 Simplifying x + 13 = 11.832159566 Reorder the terms: 13 + x = 11.832159566 Solving 13 + x = 11.832159566 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-13' to each side of the equation. 13 + -13 + x = 11.832159566 + -13 Combine like terms: 13 + -13 = 0 0 + x = 11.832159566 + -13 x = 11.832159566 + -13 Combine like terms: 11.832159566 + -13 = -1.167840434 x = -1.167840434 Simplifying x = -1.167840434

Subproblem 2

x + 13 = -11.832159566 Simplifying x + 13 = -11.832159566 Reorder the terms: 13 + x = -11.832159566 Solving 13 + x = -11.832159566 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-13' to each side of the equation. 13 + -13 + x = -11.832159566 + -13 Combine like terms: 13 + -13 = 0 0 + x = -11.832159566 + -13 x = -11.832159566 + -13 Combine like terms: -11.832159566 + -13 = -24.832159566 x = -24.832159566 Simplifying x = -24.832159566

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-1.167840434, -24.832159566}

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